A follow-up to the 437 post, this time applying the same methodology to Khafre and the other two pyramids.

If you have seen my papers then you will know that Khafre is often connected to the number 3. This same idea pops up here.

So …. Khafre has a base length of 411 ₢. 411 – 3 is 408.

If we had a square with side 408, then the diagonal would be 408√2, or 576.999.

If we divide 1000 by that (a process which effectively takes the inverse, and fixes the location of the decimal point), then we get

1000/576.999 = 1.733104858, which is a close approximation of √3 … it differs by 0.0010540… Accuracy is of course limited by having to start with whole-cubit dimensions.

I have tried the same approach with the other two pyramids, as follows. SInce we are using smaller dimensions to start with, accuracy does suffer a bit: