# The Great Pyramid and the Speed of Light

This is not original research, I’m just republishing results found by others, because I find it excessively annoying (as in: This should not be so.) and need to get it out of my system.

Location of Great Pyramid centre

As you can see, the latitude (degrees north of the equator) is 29.979187°, depending on exactly where you click on the top, the “187” changes slightly, but the above is good enough for our purposes.

If we work to four decimal places, that is 29.9792.

Now we consider the speed of light, in metres per second, which is: 299,792,458 m/s.

As you can see, that’s very close to a multiple of the latitude of the pyramid.

But that’s just a co-incidence, you say. Just a fluke, albeit a big fluke. It presupposes that the builders knew not only the metre, but the second, and could measure or know of the speed of light in those units (as opposed to, for example, 186000 miles/second).

So like an over-confident magician, they did it again.

We draw a circle inside the pyramid (touching the inner walls) and one outside (touching the four corners), as follows (which is slightly badly drawn, possibly Google’s rendering has put the centre slightly left, but you get the idea.):

Pyramid circles

Now each side of the pyramid has a designed length of 440 cubits.

So the circumference of the red inner circle is 440π, which is 1382.300 cubits.

For the circumference of the blue outer circle, we first calculate the diameter using Pythagoras:

diameter = √(440² + 440²) = 622.2539674 cubits. Then we multiply by π to get the circumference, which is 1954.868 cubits (working to 3 decimals).

Now we subtract to find the difference.

1954.868 – 1382.300 = 572.568 cubits.

Now the magician pulls the rabbit out of the hat, by converting to metres (x π/6):

572.568 x π / 6 = 299.7959037 metres… which again gives us a figure (299.79) very close to the speed of light ….

So you really need to wonder if someone was trying to send a message ….