The Spooky Stuff

To borrow a phrase from Robert Bauval, this falls under the Spooky Stuff category.

It is a very strange connection between the Grand Metre (1 + royal cubit), the base of the natural logarithm ⅇ, and the royal cubit as measured in inches.

2018-11-29: added Spooky Stuff 7 and 8
2018-12-03: added Spooky Stuff 9
2018-12-04: added Spooky Stuff 10
2019-04-24: added Spooky Stuff 11

Royal cubit, e and inch

I have no explanation for this. It just highlights again the ancient origins of the metre, inch and royal cubit, and how they mysteriously link together with π and ⅇ. But what about φ you ask?…. here you go:

Royal cubit, phi and yard

Questions for bonus marks:


Squares and double squares

Digits 0 to 6

Grand Metre, Royal cubit, RC in inches …

Royal cubit, grand metre, pi and e

The magic of the Egyptian foot.

Seven shrieks for the nautical mile

For Spooky Stuff 10, it’s a bit more long-winded than the ones above, so need to post it in chunks.

We start with this equation as a good approximation for the Grand Metre, which is equal to 1 + the Royal Cubit:

(1 + pi )/ e

Now if we consider this equation, similar to the above:

(x + pi) / e

We can solve for x:

Solve for x

Now If we use

Foot formula

as a very close approximation for the English foot ( 0.3047197551 versus 0.3048 )


Six foot formula

Which is the same as the solution for x above, to 4 decimal places.


(1 + pi) / e

gives us the Grand Metre which is 5 English feet, while the solution to

(x + pi_ / e

gives us 6 English feet.

Spooky Stuff 11

We have already seen on other pages about the cubit, how the natural logarithm base e pops up in approximations of the royal cubit, for example {\varphi e} \over 8.4 or {{1 + \pi} \over {e}} -1 = ₢

There’s even a formula to approximate the inch, as follows: {\pi e} \over 336

Then yesterday Youtube delivered up two interesting videos:

and one of the videos in this series, can’t find the exact one now:

Anyway they point out an interesting correlation between e and the imperial foot, which goes like this:

e – 1 = 2.71828 – 1 = 1.71828

1 inch = 25.4mm, so 1 foot = 12 x 25.4 = 30.48 mm.

Convert to metres, gives 0.3048 m

The royal cubit ₢ = π/6 = 0.5236 m

Divide the cubit by the foot …. 0.5236 / 0.3048 = 1.7178 (all calculations rounded to 4 decimals so far)

If we subtract actual answer above from (e – 1), we get 0.000438 … which is a fraction of a millimetre difference ( less than 500 microns which is less than the length of a grain of sand, salt or sugar) between (e -1) and ₢/foot.

Which neatly links ₢, e and the foot…. and from the foot back to the inch.

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